Run ID | 作者 | 问题 | 语言 | 测评结果 | Time | Memory | 代码长度 | 提交时间 |
---|---|---|---|---|---|---|---|---|
1937 | 吴奕希 | 11加密规则 | C++ | Accepted | 0 MS | 264 KB | 494 | 2023-12-02 17:13:33 |
# include<iostream> using namespace std; int main() { int mima,a,b,c,d,e,f,n2,n3,n4,n5,n6; char n1; cin>>mima; f = mima%10; e = mima/10%10; d = mima/100%10; c = mima/1000%10; b = mima/10000%10; a = mima/100000; n1 = a+65; n2 = b; if(b%2==0) { n2 /= 2; } n3 = (a+b+c)%10; n4 = d; n5 = (209+e)/10%10; n6 = (a+b+c+d+e+f)%10; printf("%c%d%d%d%d%d", n1, n2, n3, n4, n5, n6); return 0; }