# include<iostream> # include<cstring> using namespace std; string s; //解法一：直接判断结束后2位/3位是否符合条件 void s1(){ cin>>s;//因为中间没有空格，可以直接用cin int lens=s.size(); if(s[lens-1]=='r'&&s[lens-2]=='e') s.erase(lens-2,2); else if(s[lens-1]=='y'&&s[lens-2]=='l') s.erase(lens-2,2); else if(s[lens-1]=='g'&&s[lens-2]=='n'&&s[lens-3]=='i') s.erase(lens-3,3); cout<<s<<endl; } //解法二，截取s字符串后2位和后3位，然后跟"er","ly","ing"比较，符合就删除 void s2(){ cin>>s; int lens=s.size(); // if(lens<2){cout<<s<<endl;return;} string er="er",ly="ly",ing="ing"; if(s.substr(lens-2)==er||s.substr(lens-2)==ly) s.erase(lens-2); else if(lens>=3&& s.substr(lens-3)==ing) s.erase(lens-3); cout<<s<<endl; } int main(){ s2(); //cin>>s; //cout<<("12"=="123"); return 0; }