Run ID:1119

提交时间:2023-07-15 15:30:39

#include <iostream> using namespace std; int main() { int n,m; int i = 0; for (i = 0;i <= 1000;i++) { cin >> n; if(i > 100000) { break; } m = m + n; } printf("%.2lf",m/i 1) ; return 0; }