Run ID:213
提交时间:2022-07-22 10:05:12
#include<iostream> #include<cstdio> #include<string> #include<iomanip> #include<cmath> using namespace std; int cifang(long long x,long long n) { if(n==0) return 1; else return cifang(x,n-1)*x; } int main(){ long long p,y; cin>>p>>y; cout<<cifang(p,y); return 0; }