Run ID:219

提交时间:2022-07-22 10:06:39

#include<iostream> #include<cstdio> #include<string> #include<iomanip> #include<cmath> using namespace std; long long cifang(int x,int n) { if(n==0) return 1; else return cifang(x,n-1)*x; } int main(){ int p,y; cin>>p>>y; cout<<cifang(p,y); return 0; }